Speeddemon
Well-known member
Here's the story:
I got an Engl Savage 60 head which only has 2 speaker outputs; an 8 Ohm and a 16 Ohm.
Now all of my 2x12 cabs are 8 Ohm (with each one having 2x 16 Ohm speakers in parallel).
So I figured, with a speaker jack plate like this, I could potentially make one cab in a sort of 'stand-alone 8 Ohm' or 'serial output to a 2nd cab to make a 16 Ohm total load.
But, I followed this wiring schematic (found here: http://www.danbecker.info/guitars/20170312SpeakerCabExt/index.html
and before hooking it up to an amp, I measured it as a single 8 Ohm cab, but once I hooked up the 2nd 8 Ohm cab, instead of 16 Ohm, it became 4 Ohm total load!
So it looks that the wiring schematic may be wrong and still creating a parallel wiring, possibly with one cab inverted phase-wise.
What's your take on it and how should I wire my jack plate so that it has 1 8 Ohm input, and a serial output?
I got an Engl Savage 60 head which only has 2 speaker outputs; an 8 Ohm and a 16 Ohm.
Now all of my 2x12 cabs are 8 Ohm (with each one having 2x 16 Ohm speakers in parallel).
So I figured, with a speaker jack plate like this, I could potentially make one cab in a sort of 'stand-alone 8 Ohm' or 'serial output to a 2nd cab to make a 16 Ohm total load.
But, I followed this wiring schematic (found here: http://www.danbecker.info/guitars/20170312SpeakerCabExt/index.html
and before hooking it up to an amp, I measured it as a single 8 Ohm cab, but once I hooked up the 2nd 8 Ohm cab, instead of 16 Ohm, it became 4 Ohm total load!
So it looks that the wiring schematic may be wrong and still creating a parallel wiring, possibly with one cab inverted phase-wise.
What's your take on it and how should I wire my jack plate so that it has 1 8 Ohm input, and a serial output?