Kapo_Polenton
Well-known member
Rogue":2kjwraob said:Start at the jack, with the DPDT switched to the upper lugs, the signal just goes to through the switch and to the 68k resistor of V1. This would be your normal circuit.Kapo_Polenton":2kjwraob said:Thanks for the reply..even simpler than that, I want to know in the image I attached, is the DPDT switch wired correctly? I'm questioning the signal flow and trying to wrap my head around whether or not it would work or if maybe it was drawn incorrectly. I agree though, i will be going with more traditional values..
Switch the DPDT switched to the lower lugs, the signal now goes to the 68k resistor of the extra tube, out of the that to the pot (which I assume is an added pot), from there back to the DPDT (we're at the middle lug left now). Since it is switched down, that signal goes the lower left lug but that is bridged via a wire to the upper right lug which goes back to the 68k of V1.
I'm with brian, though, I'd do it in such a way you're not making the first stage switchable. It may work fine, idk, but I don't think that is standard. You also wouldn't have to fool with added an extra gain knob....you'd just use your existing one.
Ahhh ok, that pot is added! (that makes a bit more sense)in terms of the wiring.. So on the Hoffman diagram, if I am adding half a tube to my 2204, I can run the input resistor to the DPDT and it to pin 7 of the new tube and I am in business?..